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Vikentia [17]
3 years ago
11

A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa

rt A What will be their mutual speed immediately after the collision? Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
DIA [1.3K]3 years ago
3 0

Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

Speed of halfback, u₂ = -5 m/s (direction is opposite)

To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s

So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.

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Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

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3 years ago
A baseball of mass 300-g is hit at a velocity of 40 m/s. If the ball is caught by the third baseman and the ball penetrates 2.0
OlgaM077 [116]

The force is -12,000 N

Explanation:

First of all, we calculate the acceleration of the ball, by using the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity of the baseball (it comes to rest)

u = 40 m/s is the initial velocity

a is the acceleration

s = 2.0 cm = 0.02 m is the displacement of the ball

Solving for a,

a=\frac{v^2-u^2}{2s}=\frac{0-40^2}{2(0.02)}=-40,000 m/s^2

Now we can calculate the average force exerted on the ball, by using Newton's second law:

F=ma

where

m = 300 g = 0.3 kg is the mass of the ball

a=-40,000 m/s^2 is the acceleration

Substituting,

F=(0.3)(-40,000)=-12,000 N

where the negative sign indicates that the direction of the force is opposite to the direction of motion of the ball.

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

8 0
3 years ago
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer dista
nadezda [96]

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s)  =  344 meters

Car B: Distance = (7 m/s) x (50 s)  =  350 meters

350 meters is a longer distance than 344 meters.

<em>Car-B traveled a longer distance</em> than Car-A did.

5 0
3 years ago
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Which is style of conclusion used in research reports
allsm [11]
A conclusion is, in some ways, like your introduction. You restate your thesis and summarize your main points of evidence for the reader.You can usually do this in one paragraph.
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3 years ago
The drawing represents a mountain bike trail. A rider began at Point 1 on the trail and stopped at Point 3. At which point did h
Citrus2011 [14]

Answer:

Point 2.

Explanation:

Potential energy is simply defined as the energy stored in an object due to its position. It is can be represented mathematically by:

P.E = mgh

Where:

P.E is the potential energy.

m is the mass of the object.

g is acceleration due to gravity.

h is the height to which the object is located.

From the above equation, we can thus say that potential energy depends on the height of the object since the mass of the object is always constant i.e as the height of the object increase, the potential energy also increases and as the height of the object decrease, the potential energy also decreases.

Now, considering the diagram in the question given, we can see that point 2 is the lowest height to which the rider is located. At this point i.e point 2, the rider will have the least potential energy.

5 0
3 years ago
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