In this case, Coulomb's Law applies:
F = 1/(4πε₀) · (Q₁Q₂/r²)
You can solve it for r:
r = √[1/(4πε₀) · (Q₁Q₂/F<span>)]
Plugging in numbers:
r = </span>√[1/(4π·8.85×10⁻¹²) · (2.5×10⁻⁶)²/0.50]
= 0.335m
The correct answer is: the two charges are 0.335m apart.
Answer:
as the fuel burns,games push against the rocket moving it upward
Answer: 
Explanation:
Given
At an elevation of 
, spacecraft is dropping vertically at a speed of 
Final velocity of the spacecraft is 
using equation of motion i.e. 
Insert the values
Therefore, magnitude of acceleration is .
Rutherford's model of the atom (ESAAQ) Rutherford carried out some experiments which led to a change in ideas around the atom. His new model described the atom as a tiny, dense, positively charged core called a nucleus surrounded by lighter, negatively charged electrons.
Answer:
8 seconds
Explanation:
From Newton's second law;
Ft = m(v-u)
F = Force applied
t = time taken
v = final velocity
u = initial velocity
20 * t = 32 (9 - 4)
20t = 32 * 5
t = 32 * 5/ 20
t = 8 seconds
