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3 years ago

Define light year please

1 answer:

6 0

Light year: a unit of astronomical distance that is equal to the distance light travels in one year.

Hope this helps! :D

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Help 30 points and willgive brainliest

MissTica

HEJEGEJDHIEBDJDHDIDGDJGJDHD

8 0

3 years ago

A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an

umka21 [38]

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

Given the following data:

Mass of cat = 2 kg

Mass of elevator = 97 kg

Acceleration = 2 $m/s^2$

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

$Total \;mass=2 + 97$

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

$Force = mass \times acceleration$

Substituting the given parameters into the formula, we have;

$Force = 99 \times 2$

Net force = 198 Newton

Read more here: brainly.com/question/24029674

3 0

2 years ago

An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e

timama [110]

Answer:

K = 80.75 MeV

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

The proton mass is equal to the antiproton mass, so:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0

3 years ago

Which of the following statements best describes the relationship between force and work?

viktelen [127]

a)., b)., and c). are completely false.
There isn't a grain of truth among them.

In Physics, the technical definition of 'Work' is (force) times (distance).

7 0

3 years ago

Which produces more gravitational force on your textbook: you or the earth?

Yuri [45]

The earth obviously because it is on Earth like we are and it has the same gravital properties. It falls when you drop it and rises when you pick it up

5 0

3 years ago