The specific heat of copper is 0.39 j/g*degrees celcius how much heat is needed to raise the temperature of 1000.0 g of copper f
1 answer:
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Answer:
F = 2.40 × N
Explanation:
given data
charge q1 = 3.95 nC
x= 0.198 m
charge q2 = 4.96 nC
x= -0.297 m
solution
force on a point charge kept in electric field F = E × q ................1
here E is the magnitude of electric field and q is the magnitude of charge
and
first we will get here electric field at origin
So net field at origin is
E = (Kq2÷r2²) - (kq1÷r1²) ...............2
put here value
E = 9[(4.96÷0.297²)-(3.95÷0.198²)]
E = 400.72 N/C ( negative x direction )
so that force will be
F = 6 × × 400.72
F = 2.40 × N
Many materials produce static charge
Given :
Initial speed of car A is 15 m/s and initial speed of car B is zero.
Final speed of car A is zero and final speed of car B is 10 m/s.
To Find :
What fraction of the initial kinetic energy is lost in the collision.
Solution :
Initial kinetic energy is :
Final kinetic energy is :
Now, fraction of initial kinetic energy loss is :
Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .