Answer:
1)
is the average rate of formation of bromine gas during the same time interval.
2)
is the average rate of consumption of
during the same time interval.
Explanation:

1 ) Rate of the reaction : R
![R=-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The average rate of consumption of 
![-\frac{d[Br^-]}{dt}=1.76\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D1.76%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
The average rate of formation of ![Br_2=\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=Br_2%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![\frac{1}{5}\times 1.76\times 10^{-4} M/s=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%5Ctimes%201.76%5Ctimes%2010%5E%7B-4%7D%20M%2Fs%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![\frac{d[Br_2]}{dt}=7.04\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D%3D7.04%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
is the average rate of formation of bromine gas during the same time interval.
2 ) Rate of the reaction : R
![R=-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The average rate of formation of ![Br_2=\frac{d[Br_2]}{dt}=1.14\times 10^{-4} M/s](https://tex.z-dn.net/?f=Br_2%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D%3D1.14%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
The average rate of consumption of ![H^+=-\frac{d[H^+]}{dt}](https://tex.z-dn.net/?f=H%5E%2B%3D-%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D)
![-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\times 1.14\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.14%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
![-\frac{d[H^+]}{dt}=3.42\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D3.42%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
is the average rate of consumption of
during the same time interval.
with redox reactions you determine if you need to add electrons and water to the different sides depending what half is oxidation and reduction