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avanturin [10]
3 years ago
10

Nuclear Processes Unit Test

Chemistry
2 answers:
Finger [1]3 years ago
8 0

Answer:

?

Explanation:

shusha [124]3 years ago
4 0

Answer:

where's the question?

Explanation:

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Can someone please help me?
Olin [163]

Answer:

c.)the reactants have the same mass as the products

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

hope it helps!

8 0
3 years ago
(20 points) True or False: A benefit of fission and fusion reactions is that it takes very little mass to release large amounts
Arlecino [84]

Answer:

Hopefully its true, its seem like true. I think its true. Sorry if i'm wrong

Explanation:

4 0
4 years ago
Five gases combined in a gas cylinder have the following partial pressures: 3. 00 atm (N2), 1. 80 atm (O2), 0. 29 atm (Ar), 0. 1
Helen [10]

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

The partial pressure has been defined as the pressure exerted by each gas in the mixture.

According to the Dalton's law of partial pressure, the total pressure of gas has been the sum of the partial pressure of the gases in the mixture.

The given partial pressure of gases in the mixture has been:

  • Partial pressure of Nitrogen, P_N_2=3\;\rm atm
  • Partial pressure of Oxygen, P_O_2=1.80\;\rm atm
  • Partial pressure of Argon, P_A_r=0.29\;\rm atm
  • Partial pressure of Helium, P_H_e=0.18\;\rm atm
  • Partial pressure of Hydrogen, P_H=0.10\;\rm atm

The total pressure of the gaseous mixture has been:

P=P_N_2\;+\;P_O_2\;+\;P_A_R\;+\;P_H_e\;+\;P_H\\P=3\;+\;1.80\;+\;0.29\;+\;0.18\;+\;0.10\;\text {atm}\\P=5.37\;\rm atm

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

For more information about partial pressure, refer to the link:

brainly.com/question/14623719

7 0
2 years ago
Please help ASAP. I'm stuck on this one question. >.<
Elenna [48]

C. A compound !hope this helps!

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Tin(II) fluoride or stannous fluoride
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