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4 years ago

Calculate the work done when a force of 4 N pulls a box along the floor for a distance of 0.3 m.

Chemistry

1 answer:

Yuki888 [10]4 years ago

8 0

Answer:

<h2>1.2 Joule</h2>

solution,

Force=4 N

Distance=0.3 m

Now,

 $work = f \times d \\ \: \: \: \: \: \: \: \: \: \: \: = 4 \times 0.3 \\ \: \: \: \: \: \: \: \: \: \: \: = 1.2 \: joule$ 

hope this helps...

Good luck on your assignment....

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A sample of propane C3H8 contains 12.2 moles of carbon atoms. How many total moles of atoms does the sample contain?

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Answer:

H = 8/3 *12.2 = 32.5

12.2 + 32.5 = 44.7

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3 years ago

Of the bonds listed below the weakest bond is _______ and the strongest is ________. A strong bond is a (stable / unstable) bond

ra1l [238]

Based on the data given of the bonds listed below, the weakest bond is C-H and the strongest bond is C ≡ C.

A strong bond is a stable bond.

<h3>Which of the bonds listed is the weakest and which is the strongest?</h3>

The strength of a bond is proportional to the amount of energy required to break or form the bond.

A weak bond will require less energy to form than a strong bond.

A weak bond is unstable while a strong bond is stable.

Data provided:

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From the data given of the bonds listed below, the weakest bond is C-H and the strongest bond is C ≡ C.

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Learn more about energy of bonds at: brainly.com/question/25086481

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3 years ago

identify the postulate of Dalton's theory that is violated by the following observations: 59.95% of one sample of titanium dioxi

Inga [223]

Answer: This violates the law of constant composition.

Explanation:

Dalton's theory is based on mainly two laws, which are law of conservation of mass and law of constant composition.

Law of constant composition states that a compound always contain the elements in the fixed ratio by their masses.

For Example: In water $(H_2O)$ , the hydrogen and oxygen are present in the fixed ratio of 1 : 9 by their mass.

We are given:

A sample of titanium dioxide having 59.95 % of titanium and another sample of titanium dioxide having 60.10 % of titanium.

As, the compound is titanium dioxide. So, the mass percent of titanium must remain the same in both the elements.

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4 years ago

A gas sample has volume 3.00 dm3 at 101

gavmur [86]

Answer:

V₂ = 21.3 dm³

Explanation:

Given data:

Initial volume of gas = 3.00 dm³

Initial pressure = 101 Kpa

Final pressure = 14.2 Kpa

Final volume = ?

Solution;

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

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V₂ = 303 Kpa. dm³/ 14.2 Kpa

V₂ = 21.3 dm³

Explanation:

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