1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ierofanga [76]
3 years ago
6

10 [25-{8-6 (16-13)}÷5​

Mathematics
1 answer:
poizon [28]3 years ago
6 0

Answer:

70

Step-by-step explanation:

to solve : start wit the inside brackets first

10 [25-{8-6 (16-13)}÷5​   start 16-3

10[25-{8-6(3)}÷5           then multiply 6 and 3

10[25-{8-18}]÷5              then subtract 8-18

10[25-(-10)]÷5                

10[25+10)÷5                  add numbers inside brackets

10×35÷5=70                 multiply and divide

You might be interested in
Last week Pizza Port served 264 vegetarian pizzas out of a total of 792 pizzas based on this data what is the probability that t
yuradex [85]

Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?

7 0
3 years ago
Question is below thanks
vichka [17]

Answer:

33.51

Step-by-step explanation:

There's a formula using the value of the angle but I don't remember it so the most easy way is:

A circle has an angle of 360°

so our section has an angle of 60

and we know that 360=60*6

so the area of the circle we divide it by 6 and we get the area we want

A=\pi r^2\\\\A=\pi (8)^2\\\\A=64\pi

divide this by 6

A_1=A/6=64\pi/6\approx 33.51 units squared

5 0
3 years ago
Read 2 more answers
In a class of 30 students, 21 play an instrument and 8 play a sport. There are 7
tigry1 [53]

Step-by-step explanation:

The formula for probability is favourable outcome/ Total outcome. So the answer might be 7/30.

7 0
3 years ago
A family has two cars. During one particular week, the first car consumed 20 gallons of gas and the second consumed 15 gallons o
OleMash [197]

Answer: the fuel efficiency of the first car is 20 miles per gallon.

the fuel efficiency of the second car is 15 miles per gallon.

Step-by-step explanation:

Let x represent the number of miles per gallon of the first car.

Let y represent the number of miles per gallon of the second car.

During one particular week, the first car consumed 20 gallons of gas and the second consumed 15 gallons of gas. The two cars drove a combined total of 625 miles. It means that

20x + 15y = 625- - - - - - - - - - 1

The sum of their fuel efficiencies was 35 miles per gallon. It means that

x + y = 35

Substituting x = 35 - y into equation 1, it becomes

20(35 - y) + 15y = 625

700 - 20y + 15y = 625

- 20y + 15y = 625 - 700

- 5y = - 75

y = - 75/ - 5

y = 15

x = 35 - y = 35 - 15

x = 20

4 0
3 years ago
What is the value of the expression 99 – 7a2 when a a = 3?
77julia77 [94]

Answer:

36

Step-by-step explanation:

plug in a=3 for a

I belive you meant 99- 7 * a^2

so 99- 7 * (3)^2 = 36

7 0
3 years ago
Other questions:
  • Drag an answer to each box to complete this paragraph proof.
    11·2 answers
  • Convert 19/40 to a decimal
    11·2 answers
  • the temperature outside was -16 degrees if the temperature dropped 10 degrees what was the current temperature
    11·1 answer
  • What is the degree of 7x + 1?
    10·1 answer
  • This is me right now
    10·1 answer
  • Find The Coordinates of point p witch cuts line segment AB into two parts with a ratio of 4:1
    9·2 answers
  • .If you travel for 18 hours a distance of 7,794 miles, what was the speed that you traveled per hour
    10·1 answer
  • It costs $525 for seven adult tickets and 12 youth tickets to the hockey game. If the difference in price between an adult ticke
    6·1 answer
  • No Links
    8·1 answer
  • What's the exact value of sin 7/12?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!