Solve for t. 3/4t = 1/4 A.1/3 B.1 C.4/3 D.4

Mathematics

2 answers:

Alika [10]3 years ago

8 0

We have..
$\frac{3}{4}t=\frac{1}{4}$

$\mathrm{Multiply\:both\:sides\:by\:}4 \ \textgreater \ 4\cdot \frac{3}{4}t=\frac{1\cdot \:4}{4} \ \textgreater \ Next\;simplify$

$4\cdot \frac{3}{4}t \ \textgreater \ \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{3\cdot \:4}{4}t$

$\mathrm{Cancel\:the\:common\:factor:}\:4 \ \textgreater \ t\cdot \:3$

$\frac{1\cdot \:4}{4} \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:1\cdot \:4=4 \ \textgreater \ \frac{4}{4}$

$\mathrm{Apply\:rule}\:\frac{a}{a}=1$

$3t=1 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}3 \ \textgreater \ \frac{3t}{3}=\frac{1}{3} \ \textgreater \ t=\frac{1}{3}$

Hope this helps!

Andreyy893 years ago

4 0

I have included a picture. In the picture you will find the work shown and the answer.

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Use the counting principle to determine the number of elements in the sample space. The possible ways to complete a multiple-cho

nadezda [96]

Answer:

The correct answer is 4294967296 possible ways to complete such a test.

Step-by-step explanation:

Step 1

The first step is to define the fundamental principle of counting. The fundamental principle of counting states that if a process can be carried out in n steps, where there are $n_1$ ways to complete the first step, $n_2$ ways to complete the second step, $n_3$ , and $n_k$ ways to complete the $k^{th}$ step, this process can be carried out in $n_1\times n_2\times n_3\times ...\times n_k$ ways.

Step 2

We use the fundamental principle of counting with $n=4$ for a total of $k=16$ steps. This test can be carried out in $4^{16}=4294967296$ ways. This comes from multiplying 4 by itself 16 times.