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3 years ago

Solve for t. 3/4t = 1/4 A.1/3 B.1 C.4/3 D.4

Mathematics

2 answers:

Alika [10]3 years ago

8 0

We have..
$\frac{3}{4}t=\frac{1}{4}$

$\mathrm{Multiply\:both\:sides\:by\:}4 \ \textgreater \ 4\cdot \frac{3}{4}t=\frac{1\cdot \:4}{4} \ \textgreater \ Next\;simplify$

$4\cdot \frac{3}{4}t \ \textgreater \ \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{3\cdot \:4}{4}t$

$\mathrm{Cancel\:the\:common\:factor:}\:4 \ \textgreater \ t\cdot \:3$

$\frac{1\cdot \:4}{4} \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:1\cdot \:4=4 \ \textgreater \ \frac{4}{4}$

$\mathrm{Apply\:rule}\:\frac{a}{a}=1$

$3t=1 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}3 \ \textgreater \ \frac{3t}{3}=\frac{1}{3} \ \textgreater \ t=\frac{1}{3}$

Hope this helps!

Andreyy893 years ago

4 0

I have included a picture. In the picture you will find the work shown and the answer.

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At the state fair 4 employees were paid $8.20 an hour to work at a corn-dog stand. They worked for 10 hours at regular pay and t

Katen [24]

Answer:

The four employees earned $ 452.80 in total

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Hour rate = $ 8.20

Overtime hour rate = $ 2.20 extra

Regular hours = 10

Overtime hours = 3

Number of employees = 4

2. How much money did they earn in total?

Let's find out the individual pay for an employee and then we'll calculate the pay for the 4 employees:

Individual pay = 10 * 8.20 + 3 * 10.40

Individual pay = $ 113.20

Total pay = Individual pay * 4

Total pay = 113.20 * 4

Total pay = $ 452.80

6 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$