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Lostsunrise [7]
3 years ago
12

Question 5 (2) x cube - 3x square 9x - 5

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0
Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.

Do you mean Question #5?  By  (2) x cube, do you mean 2x^3?

I strongly suggest that you use lots of parentheses (   ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.    

If only you'll clear this up, I'd be happy to help.

I will assume that your post is   2x^3 - 3(9x-5)^2.

Then 2x^3 - 3(81x - 90x + 25).  Does this have any resemblance to what you wanted me to see in your post?

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andrew-mc [135]

Answer:

False

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true

Step-by-step explanation:

65x+105=y

Substitute 6 for x to find the cost for 6 classes

65(6)+105=y

390+105=y

495=y

4 0
2 years ago
6. The basketball team scored points by
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Answer:

36, 2×2×3×3

Step-by-step explanation:

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3 years ago
A store uses the expression -2p+ 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere
Ivan

Answer:

B: $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00.

Step-by-step explanation:

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3 years ago
A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
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