Question 5 (2) x cube - 3x square 9x - 5

1 answer:

3 0

Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.

Do you mean Question #5? By (2) x cube, do you mean 2x^3?

I strongly suggest that you use lots of parentheses ( ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.

If only you'll clear this up, I'd be happy to help.

I will assume that your post is 2x^3 - 3(9x-5)^2.

Then 2x^3 - 3(81x - 90x + 25). Does this have any resemblance to what you wanted me to see in your post?

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Help me please it just hard for a newbie like me

Makovka662 [10]

Hello there,
Part 1:
Perimeter of Red = 11+11+11+11
= 44
Perimeter of Blue= 6+6+6+6
= 24
Ratio: Red : Blue
44 : 24(divide by 4)
11 : 6
Part 2:
Area of Red= 11 x 11
= 121
Area of Blue= 6 x 6
= 36
Ratio: Red : Blue
121: 36

Hope this helps :))

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The perimeter of a rectangle is 200 yards. what are the dimensions of the rectangle if the length is 80 yards more than the? wid

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An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

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