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ankoles [38]
3 years ago
6

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam, which of the following is the number of senior

s who scored above 96%? O 10
Mathematics
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

\frac{2}{100}\times50

\frac{100}{100}

1

Hence, the number of seniors who scored above 96% is 1.

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How do you solve -1/2 (-3/2 + 6x +1) -3x?
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Apply distributive property:
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Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

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However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
3 years ago
Read 2 more answers
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