Answer:
1. 30°
2.90°
3. 12 units
Step-by-step explanation:
I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)
1.
The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.
2.
If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.
3.
Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.
Sorry if this is all dreadfully wrong, and I hope I helped you!
I think it is..................
Answer:
There are 17,418,240 different ways to choose the teams.
Step-by-step explanation:
Arrangements of n elements:
The number of possible arrangements of n elements is given by:

In how many different ways can the teams be chosen so that the number of employees on each project are as follows: 9, 4, 2?
This is:
Arrangement of 9 elements, followed by an arrangement of 4 elements followed by an arrangement of 2 elements. So

There are 17,418,240 different ways to choose the teams.
Answer:
x - 5 = x - 2 and
x - 5 = 2 - x.
Step-by-step explanation:
x - 5 may be positive or negative so we have:
x - 5 = x - 2
and
x - 5 = - (x - 2)
x - 5 = 2 - x.
The greatest common factor is 2
We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.
With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.