Differentiate both sides with respect to
When
For part (b), we now assume that
where the chain rule is used on the right side. We're told that
where the unit is again units/second.
Triangle ABC is equilateral. Find the height of BD
1 answer:
Since ABC is equilateral, all 3 sides have equal length. side AC is 8 units since side BC is 8 units.
Line BD is placed in the middle, making D the midpoint of side AC.
knowing this information we can determine that the length of DC is 4 units (half of AC)
since triangle BDC is a right triangle, we can use the side lengths in the pythagorean theorem to find the length of BD
a²+b²=c² where a & b = legs of triangle , and c= hypotenuse (longest side)
we are given the hypotenuse and found one leg so we can plug our values into the equation to find the third
4² + b²= 8²
16 + b² = 64
b² = 48
b =
b= 4√3 or about 6.928 units
hope this helped
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Differentiate both sides with respect to
When
For part (b), we now assume that
where the chain rule is used on the right side. We're told that
where the unit is again units/second.
Answer:
Kimberly and Mike had at first $100 each
Step-by-step explanation:
Assume that Kimberly and Mike each have $x
∵ Kimberly has $x
∵ Kimberly spent $50
- Find the reminder with Kimberly by subtracting 50 from x
∴ The money left with Kimberly = x - 50
∵ Mike has $x
∵ Mike spent $25
- Find the reminder with Mike by subtracting 25 from x
∴ The money left with Mike = x - 25
∵ Mike's money is 50% more than Kimberly's money
- That means Mike's money is more than Kimberly's money by
50% of Kimberly's money
∴ x - 25 = (x - 50) + 50%(x - 50)
∵ 50% = = 0.5
∴ x - 25 = (x - 50) + 0.5(x - 50)
- Simplify the right hand side
∴ x - 25 = x - 50 + 0.5x - 25
- Add the like terms in the right hand side
∴ x - 25 = 1.5x - 75
- Add 75 to both sides
∴ x + 50 = 1.5x
- Subtract x from both sides
∴ 50 = 0.5x
- Divide both sides by 0.5
∴ 100 = x
∵ x represents the amount of money that Kimberly and
Mike each had at first
∴ Kimberly and Mike had at first $100 each