Question

The per capita consumption of red meat by people in a country in a recent year was normally​ distributed, with a mean of 107107 pounds and a standard deviation of 39.339.3 pounds. Random samples of size 1818 are drawn from this population and the mean of each sample is determined.

Answer 1

Answer:

mean sample is 9.26

Step-by-step explanation:

Given data

mean = 107 pounds

standard deviation = 39.3 pounds

no of sample (n) = 18

to find out

sample means

solution

according to question we know mean of sample = 107 pounds

so standard error of this sample will be standard deviation / $\sqrt{n}$

now put all value n and standard deviation and we get sample mean i.e.

mean sample = standard deviation / $\sqrt{n}$

mean sample =  39.3 / $\sqrt{18}$

mean sample = 9.26