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charle [14.2K]
3 years ago
7

The maximum weight allowed per car on The Twister carnival ride is 263 pounds. Your friend weighs 86 pounds. To be able to ride

in a car together, how much can you weigh? Write and solve the inequality. A. x + 177 ≤ 263; at most 86 pounds B. x - 86 ≤ 263 at most 177 pounds C. x +86 ≤ 263; at most 177 pounds D. x + 86 ≤ 177; at most 263 pounds
Mathematics
1 answer:
Kazeer [188]3 years ago
4 0
Your weight:   x lb
Friend's wt.:  86 lb
Max wt. allowed:  263 lb

Then x + 86 ≤ 263, with x in lb.  You could weigh a max. of 177 lb and still be able to go on this ride.

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nexus9112 [7]
Compare the small marks on the lines of the triangles, if you draw them both out next to each other, are they exactly the same? If so, they’re congruent
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3 years ago
Stephanie has the same number of dimes and nickels. She has $6.10 in all. Write an equation that you could use to find the numbe
Igoryamba

Answer:

The equation is

15x = 610

Step-by-step explanation:

A dime is 10 cents while a nickel is 5 cents

$6.10 is same as 610 cents

Let the number of dimes and number of nickels be x

10x + 5x = 610

15x = 610

5 0
3 years ago
Carey earns $9.75 working part time on weekends. The table below shows the amount, a, Carey earns for working h hours.
shutvik [7]
$29.25 in 3 hours. explanation: if he makes $9.75 in 1 hour then 9.75 x 3 (hours) would equal $29.25
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3 years ago
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end
zalisa [80]

we know that

4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}

6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}

To find how long are 6\frac{1}{2}  sections placed end to end

Multiply the number of sections by the length of one section

so

\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft

\frac{169}{6}\ ft =28\frac{1}{6}\ ft

therefore

<u>the answer is</u>

28\frac{1}{6} \ ft


6 0
3 years ago
Read 2 more answers
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