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Tamiku [17]
3 years ago
11

Help me please ??!!!!

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
7 0
The answer has to be A or C but most likely A
grandymaker [24]3 years ago
5 0
The answer is a 100% sure
You might be interested in
Simplify 5x + 2(x - 3) = -2(x - 1)
Kruka [31]

Answer:

x=8/9

Step-by-step explanation:

5x+2(x-3)=-2(x-1)

1) Distribute 2 to x and -3:

5x+2x-6=-2(x-1)

2) Distribute -2 to x and -1:

5x+2x-6=-2x+2

3) Combine alike terms:

7x-6=-2x+2

4) Add 2x to both sides:

9x-6=2

5) Add 6 to both sides:

9x=8

6) Divide both sides by 9:

x=8/9

8 0
4 years ago
Read 2 more answers
The first two steps in determining the solution set of the system of equations, y = -x2 + 4x + 12 and y=-3x + 24,
PSYCHO15rus [73]

Answer:

C

Step-by-step explanation:

(3,15) and (4,12)

5 0
3 years ago
N+16=9 solve for variable
Aleks [24]

Answer:

N= -7

Step-by-step explanation:

N+16=9

subtract 16 from both sides

N= -7

8 0
3 years ago
A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and
Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95  

= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95  

=P( z \leq \displaystyle\frac{x - 5}{1})=0.05  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4  

Hence,  4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0
3 years ago
Can you help with number 18 please?
motikmotik

16.1 - 0.25 = 15.85
6 0
3 years ago
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