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Lisa [10]
3 years ago
9

find the values of x that would make the area of the rectangle greater than the area of the triangle.can you help me pls​

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

x>3

Step-by-step explanation:

The\ area\ of\ the\ rectangle\ in\ terms\ of\ x=6x\\The\ area\ of\ the\ triangle\ in\ terms\ of\ x=\frac{4(x+6)}{2}=2(x+6) \\Given\ condition:\\The\ area\ of\ the\ rectangle>The\ area\ of\ the\ triangle\\Hence,\\6x>2(x+6)\\Now, as\ practically\ any\ of\ the\ side\ of\ the\ polygons\ cannot\ be\ negative.\\\\Hence,\\6x>2x+12\\6x-2x>2x+12-2x\\4x>12\\\frac{4x}{4} >\frac{12}{4} \\x>3

Hence,\\x\ could\ be\ any\ real\ number\ greater\ than\ 3.

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2/5, 4/7, 5/2

Step-by-step explanation:

5/2=2.5     2/5=.40    4/7= .59 that's aproximately  for 4/7

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<h2><em><u>2a</u></em></h2>

Step-by-step explanation:

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20 divided by 2 (5+5)=
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<span>The correct answer is 1.

Explanation:
The way this is written, everything after the words "divided by" would be calculated first; it is written as though this is a grouping, such as 20/(2*(5+5)). We would evaluate the innermost parentheses first; 5+5=10. Then this gives us 2*10=20 in our parentheses. 20/20 = 1.</span>
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An activity has an optimistic time estimate of 25 days, a most likely estimate of 29 days, and a pessimistic estimate of 34 days
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The expected duration of the activity is 29 days and 4 hours.

Step-by-step explanation:

Step 1:

The optimistic time, t_{o} = 25 days,

The most likely estimate, t_{m} = 29 days.

The pessimistic time, t_{p} = 34 days.

According to PERT, the expected duration of the activity, t_{e} = \frac{t_{0}+4t_{m} +t_{p}  }{6}.

Step 2:

By substituting the given values, we gett_{e} = \frac{t_{0}+4t_{m} +t_{p}  }{6} = t_{e} = \frac{25+4(29) +34  }{6} = \frac{175}{6} = 29.1666.

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29.1666 days approximately equal 29 days and 4 hours.

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3 years ago
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