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kipiarov [429]
3 years ago
5

The square of a number, decreased by 15, is equal to twice the number

Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0
the answer to this equation x^2-15=2x
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Please answer with explanation if nonsense answers I will report so please answer properly​
alexgriva [62]

Answer:

  • x = 2

Step-by-step explanation:

<u>We know that</u>

  • The diagonals of a rectangle are of equal length
  • The diagonals bisect each other

<u>Considering the above we have:</u>

  • EG = HF = 2JF = 2JH

<u>Substitute the given values and solve for x:</u>

  • 24x - 8 = 2*(8x + 4)
  • 24x - 8 = 16x + 8
  • 24x - 16x = 8 + 8
  • 8x = 16
  • x = 16/2
  • x = 2
3 0
3 years ago
Two similiar rectangles have corresponding sides in the ratio 10:3. What is the ratio of their areas
lianna [129]

Answer:

Step-by-step explanation:

The ratio of its areas is equal to

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem the scale factor is equal to the ratio 10:3

Let

z-------> the scale factor

so

z2=(10/3)2=100/9

7 0
3 years ago
I need help on this one asap pliz
Doss [256]
C(5,4)(.40)^4(1-.40)^1=5(.4)^4(.6)^1=0.0768

That's 7.68% = 7.7% (rounded)

Note: C(5, 4) is the number of combinations of 5 things taken 4 at a time. You may have seen this written as _5C_4

In general, C(n,r)=\frac{n!}{r!(n-r)!}
8 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
Really confused with this one it is related with similar triangles please help
Nonamiya [84]

Answer:

x=20

y=70/3 which is about 23.3

Step-by-step explanation:

Write a proportion of all similar sides

6 0
3 years ago
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