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3 years ago

You had $150, but you are spending $2 each day.What algebraic expression models this situational?

Mathematics

1 answer:

kobusy [5.1K]3 years ago

3 0

Hello!

First, set a variable for "spending $2 each day". This is important as the number of days passed is not set, and it varies, so we need a variable for it. Say d = number of days passed.

Now, write out the equation. The first thing we want to write is "You had $150". This can be represented by just writing out the number 150.

Our equation now: 150

Finally, add the variable. This would be "you are spending $2 each day". For this, you must subtract 2 times d from 150.

Our final equation: 150 - 2d

Hope this helps!

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expeople1 [14]

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2 years ago

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Answer:

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2 years ago

Picture attached with question

Mariana [72]

The function is stretched vertically by a factor of 3.

The function shifts 2 to the right.

The function is moved 5 units up.

Explanation:

The parent function of the graph is $f(x)=\sqrt{x}$

The transformation for the parent function is given by $g(x)=3\sqrt{x-2} +5$

Thus, the transformed function is in the form of $y=a\sqrt{x-h} +k$

where a is the vertical compression/stretch,

h moves graph to left or right and

k moves the graph up or down.

Thus, from the transformed function $g(x)=3\sqrt{x-2} +5$ , we have,

$a=3, h=2 , k=5$

The attached graph below shows the transformation of the graph that the graph is stretched vertically by a factor of 3 and shifted 2 units to the right and moved 5 units up.

Hence, The function is stretched vertically by a factor of 3.

The function shifts 2 to the right.

The function is moved 5 units up.

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3 years ago

A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi

lisov135 [29]

<h2>Answer:</h2>

$\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle $11\pi /2=165^{\circ}$ , therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry: