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Anna [14]
3 years ago
12

Liza's cat had six kittens. When Liza and her brother weigh all the kittens together, they weigh 4 pounds and 2 ounces. Since al

l the kittens are about the same size, how many ounces does each kitten weigh?
Mathematics
2 answers:
amid [387]3 years ago
7 0
They would each be about 0.6875 pounds or 11 ounces.
balandron [24]3 years ago
3 0
Each kitten should weigh 11.33 oz 

-one pound=16 oz

4*16=66
66+2=68
68/6(kittens)=11.33 oz


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If you subtract for 4 from 7 in the first expression, then h is less than or equal to 3.

If you subtract 1 from 3 in the second expression then h is greater than 2.

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An industrial psychologist consulting with Lara music stores knows that the average number of complaints management receives eac
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Step-by-step explanation:

H0 : μ ≥ 6

H1 : μ < 6

Test statistic :

n = 20

Sample Mean, x = 3

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Test statistic = (3 - 6) ÷ 1.5/sqrt(20)

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Tcritical at 0.05, df = 19 = - 1.729

Tstatistic < Tcritical

−8.944271 < - 1.729

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We can conclude that there is significant evidence that the number of complaints received by Lara music store is different from number of complaints received by music stores in general.

3 0
3 years ago
What is the mean, median, and mode of 3,8,13,4,9,15,7,8,5,
Stella [2.4K]

Answer:

Mean:  8

Median:  8

Mode:  8

Step-by-step explanation:

Find the average

Mean: 3 + 4 + 5 + 7 + 8 + 8 + 9 + 13 + 15 = 72

Divide by the amount on numbers:  72 / 9 = 8

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What is <br> 35g−13=−103<br> g=
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g= 13/138

Step-by-step explanation:

1

Add

1

3

13

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to both sides of the equation

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Simplify

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Divide both sides of the equation by the same term

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8 0
3 years ago
Mrs. Welch and her 5 children are shopping at a local grocery store. Each of the children will be allowed to select one box of c
lara [203]
<h3>Answer:  462</h3>

==================================================

Explanation:

Let's call the children A, B, C, D, E for the sake of simplicity. Also, let's have the children select in alphabetical order.

  • Child A has 11 choices to pick from.
  • Child B has 10 choices to pick from
  • Child C has 9 choices to pick from
  • Child D has 8 choices to pick from
  • Child E has 7 choices to pick from

We started at 11 and counted down by 1 until we had all the children selecting.

Multiply out these values: 11*10*9*8*7 = 55440

There are 55440 different permutations possible. If order mattered, then we would stop here. However, order does not matter because the cereals aren't ranked and their position doesn't matter. All that matters is what fills the grocery cart. In other words, imagine the kids jumbling up the boxes as they push around the cart, so the order would be irrelevant.

Consider a group of 5 items. There are 5! = 5*4*3*2*1 = 120 different ways to arrange the five items in this group. So for any 5 cereals picked, there are 120 ways to order them. But again, order doesn't matter, so we have to correct for this over-counting. We do this by dividing by 120

55440/120 = 462

------------------

If you want to use a formula, then plug n = 11 and r = 5 into the combination formula below and simplify.

n C r = (n!)/(r!(n-r)!)

11 C 5 = (11!)/(5!*(11-5)!)

11 C 5 = (11!)/(5!*6!)

11 C 5 = (11*10*9*8*7*6!)/(5!*6!)

11 C 5 = (11*10*9*8*7)/(5!)

11 C 5 = (11*10*9*8*7)/(5*4*3*2*1)

11 C 5 = 55440/120

11 C 5 = 462

We get the same answer.

8 0
3 years ago
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