Answer:
5.6 L is the final volume for SO₂ at STP condtions
Explanation:
The reaction is: S(s) + O₂ (g) → SO₂ (g)
Ratio for this reaction is 1:1, if we see stoichiometry.
1 mol of sulfur can react to 1 mol of oxygen in orden to produce 1 mol of sulfur dioxide.
Then, 0.250 moles of sulfur can produce 0.250 moles of SO₂.
If we solve this by a rule of three, we can say:
At STP 1 mol occupies 22.4L
Then, 0.250 moles will be contained at (0.250 mol . 22.4L) /1mol = 5.6 L
If we apply the Ideal Gases Law:
P . V = n . R . T
1 atm . V = 0.250 mol . 0.082 . 273K
V = (0.250 mol . 0.082 . 273K) / 1atm → 5.6 L
The balanced equation for the reaction is
C₃H₈ + 5O₂ → 3CO₂ + 4H₂<span>O
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of the </span>C₃H₈ = 0.025 g
Molar mass of C₃H₈ = <span>44.1 g/mol
Hence, moles of </span>C₃H₈ = 0.025 g / 44.1 g/mol = 5.67 x 10⁻⁴ mol
The stoichiometric ratio between C₃H₈ and O₂ is 1 : 5.
Hence, moles of O₂ = moles of C₃H₈ x 5
= 5.67 x 10⁻⁴ mol x 5
= 2.835 x 10⁻³ mol
Molar mass of O₂ = <span>32.00 g/mol
Hence, mass of O</span>₂ = moles x molar mass
= 2.835 x 10⁻³ mol x 32.00 g/mol
= 0.09072 g
Hence, needed O₂ for the reaction is 0.09072 g.
Answer:
The disadvantages or the limitations are as follows:
Dot structures: based on an empirical trend “atoms like octets”, not a rigorous description of the true nature of electrons
Arrow and line diagrams: Does not say much of the possible properties of the molecule.
Written electron configurations: no 3D representation of the molecule or the atom
Explanation:
please mark my answer as brain list
The number of protons. hope this helps. :)
Explanation:
There are several ways to define acids and bases, but pH and pOH refer to hydrogen ion concentration and hydroxide ion concentration, respectively. The "p" in pH and pOH stands for "negative logarithm of" and is used to make it easier to work with extremely large or small values. pH and pOH are only meaningful when applied to aqueous (water-based) solutions. When water dissociates it yields a hydrogen ion and a hydroxide.