Answer:
-3.5m/s²
Explanation:
Given
Initial Velocity, u = 30m/s
Final Velocity, v = 23m/s
Time, t = 2.0s
Required
Determine the magnitude of acceleration
This is calculated using first equation of motion.
v = u + at
Substitute values for v, u and t
23 = 30 + a * 2.0
23 = 30 + 2.0a
23 - 30 = 2.0a
-7 =2.0a
Solve for a
a = -7 ÷ 2.0
a = -3.5m/s²
Answer: 2mph
Explanation:
In relative vector : Considering objects A and B
a) when two objects are moving in the same direction
Vab = Va + Vb
b) when two objects are moving in an opposite direction
Van = Va - Vb
Hence, this rule will be applied.
Speed upstream = ( 33-v ) opposite direction of the current
Downstream = ( 33+v ) same direction with the current
Distance = speed × time
Time upstream = 35/60
Time downstream = 31/60
From the formulae distance = speed × time
Upstream = ( 33-v ) × 35/60 ............ 1
Downstream = ( 33+V ) × 31/60 .............. 2
Equate 1 and 2
33-v) ×35/60 = 33+V) ×31/60
Multiply both side by 60
1155-35v = 1023+31v
1155-1023 = 31+35
132 = 66v
V = 2mph
The force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
<h3>Force of the object</h3>
F = mv/t
where;
- m is mass of the object = 200 kg
- v is velocity of the object = 60 m/s
- t is time of motion = 5 mins = 300 seconds
F = (200 x 60)/(300)
F = 40 N
<h3>Velocity of the object</h3>
F = mv/t
Ft = mv
v = Ft/m
where;
- m is mass = 600 kg
- F is force = 150 N
- t is time = 2 mins = 120 s
v = (150 x 120)/(600)
v = 30 m/s
Thus, the force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
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Answer:-2.61 m/s
Explanation:
This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum must be equal to the final momentum :
(1)
Where:
(2)
(3)
is the mass of the first car
is the velocity of the first car, to the North
is the mass of the second car
is the mass of the second car, to the South
is the final velocity of both cars after the collision
(4)
Isolating :
(5)
(6)
Finally:
(7) This is the resulting velocity of the wreckage, to the south