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Studentka2010 [4]
3 years ago
14

Why do ions stick together?

Physics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

The ions stick together because of the electrostatic attraction between ions that are near one another.Electrostatic attraction refers to the electrostatic force of long-range interaction occurring between the attractive electrostatic adsorption in aqueous solution with differently charged particles or uncharged particles.

Hope this helps!! ;)

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Would this be reflection or refraction?
JulsSmile [24]
That is a refraction darlin
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A car goes forward along a level road at constant velocity. The additional force needed to bring the car into equilibrium is
liraira [26]

Answer: Frictional force

Explanation:

Since the body is moving at constant velocity, this means that the acceleration of the body is zero. Frictional force is a force of opposition which tends to oppose the moving force of an object on a flat surface.

Mathematically, summation of force on the car along the road will be

Fm - Ff = ma

Fm = moving force

Ff = frictional force

m = mass of the body

a = acceleration of the body

Since a = 0, we have;

Fm -Ff = 0

Fm = Ff (which shows that the two forces acting on the body are equal and opposite)

This frictional force will tend to keep the body at equilibrium.

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3 years ago
How do I spell pineapple apple pen
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Answer:

ppap

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idk man :vvvv. v vv.

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3 years ago
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SIZIF [17.4K]
The correct answer is the Sun.i hope that helped! if you have any questions or concerns about the answer i gave you please let me know!!
4 0
4 years ago
023 (part 1 of 2) 10.0 points
Annette [7]

Answer:

Part 1

The angular speed is approximately 1.31947 rad/s

Part 2

The change in kinetic energy due to the movement is approximately 675.65 J

Explanation:

The given parameters are;

The rotation rate of the merry-go-round, n = 0.21 rev/s

The mass of the man on the merry-go-round = 99 kg

The distance of the point the man stands from the axis of rotation = 2.8 m

Part 1

The angular speed, ω = 2·π·n = 2·π × 0.21 rev/s ≈ 1.31947 rad/s

The angular speed is constant through out the axis of rotation

Therefore, when the man walks to a point 0 m from the center, the angular speed ≈ 1.31947 rad/s

Part 2

Given that the kinetic energy of the merry-go-round is constant, the change in kinetic energy, for a change from a radius of of the man from 2.8 m to 0 m, is given as follows;

\Delta KE_{rotational} = \dfrac{1}{2}  \cdot I \cdot \omega ^2 = \dfrac{1}{2}  \cdot m \cdot v ^2

I  = m·r²

Where;

m = The mass of the man alone = 99 kg

r = The distance of the point the man stands from the axis, r = 2.8 m

v = The tangential velocity = ω/r

ω ≈ 1.31947 rad/s

Therefore, we have;

I = 99 × 2.8² = 776.16 kg·m²

\Delta KE_{rotational} = 1/2 × 776.16 kg·m² × (1.31947)² ≈ 675.65 J

3 0
3 years ago
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