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lara31 [8.8K]
2 years ago
9

The object was thrown vertically upwards at a speed of 30 m / s. How high does the body go?

Physics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

4.9

Explanation:

Velocity half second before maximum height = Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity u=0 m/s

We have g=9.8 m/s

Time t= ½s

s

Thus velocity after half second v=u+gt

v=0+9.8× ½ =4.9m/s

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Consider a long rod of mass, m, and length, l, which is thin enough that its width can be ignored compared to its length. The ro
ehidna [41]

Answer:

Explanation:

The rod will act as pendulum for small oscillation .

Time period of oscillation

T=2\pi\sqrt{\frac{l}{g} }

angular frequency ω = 2π / T

= \omega=\sqrt{\frac{g}{l} }

b )

ω = 20( given )

velocity = ω r = ω l

Let the maximum angular displacement in terms of degree be θ .

1/2 m v ² = mgl ( 1 - cosθ ) ,

[ l-lcosθ is loss of height . we have applied law of conservation of mechanical energy .]

.5 (  ω l )² = gl( 1 - cos θ )

.5 ω² l = g ( 1 - cosθ )

1 - cosθ  = .5 ω² l /g

cosθ = 1 - .5 ω² l /g

θ can be calculated , if value of l is given .

4 0
3 years ago
Superman can fly 600 miles in 2 in a half hours what is his speed
Digiron [165]

To solve for distance use the formula for distance d = st, or distance equals speed times time.

distance = speed x timeSpeed

so the answer is 240 miles per hour.

4 0
3 years ago
Distinguish between nonsampling error and sampling error. Choose the correct answer below.
kiruha [24]

Answer:

The correct answer is D.

Non-sampling error is the error that results from​ under-coverage, non-response​ bias, response​ bias, or​ data-entry errors. Sampling error is the error that results because a sample is being used to estimate information about a population.

Explanation:

Sampling error is related to the variation between the true values of the sample and the population. If occurred, it is always random depending upon the sample chosen.

Non-sampling error can be random as well as non-random. Non-sampling error can occur irrespective of the sample chosen. It is related to the inappropriate analysis of the data.

5 0
3 years ago
A 75 kV x-ray machine gives an exposure of 200 mR for a 0.2-sec chest x-ray exam.
pashok25 [27]

Explanation:

Given that,

Potential = 75 kV

Exposure = 200 mR

Time = 0.2 sec

We need to calculate the x-ray fluence during this chest x-ray exam

Using formula of fluence

x-ray\ fluence=exposure\times time

Put the value into the formula

x-ray\ fluence=200\times0.2

x-ray\ fluence=40\ mRs

We need to calculate the energy fluence

Using formula of energy fluence

E_{f}=40\times10^{-3}\times75\times10^{3}

E_{f} = 3000\ J

We need to calculate dose -equivalent delivered to the bone, muscle, and fat

Using formula of dose

D=\dfrac{E}{t}

Where, D = dose

E = energy

t = time

Put the value into the formula

D=\dfrac{3000}{0.2}

D=15.0\ kJ

Hence, This is the required solution.

7 0
3 years ago
You have arrived at the scene of a two car accident. You know the following pieces of information:
Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 2000 kg is the mass of the first car

u_1 is the initial velocity of the first car

v_1 = 10 m/s is the final velocity of the first car (taking right as positive direction)

m_2 = 2000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v_2 is the final velocity of the second car

We also know the initial momentum of car 1, which is

p_1 =40,000 kg m/s

And since momentum is the mass times the velocity, we find the initial velocity of car 1:

u_1 = \frac{p_1}{m_1}=\frac{40,000}{2,000}=20 m/s

with a positive sign, since the direction is to the right.

Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:

v_2 = \frac{m_1 u_1 -m_1 v_1}{m_2} = \frac{(2000)(20)-(2000)(10)}{2000}=10 m/s

And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

8 0
3 years ago
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