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lara31 [8.8K]
2 years ago
9

The object was thrown vertically upwards at a speed of 30 m / s. How high does the body go?

Physics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

4.9

Explanation:

Velocity half second before maximum height = Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity u=0 m/s

We have g=9.8 m/s

Time t= ½s

s

Thus velocity after half second v=u+gt

v=0+9.8× ½ =4.9m/s

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The correct answer is Destructive Interference.

Consider the image attached below. Two waves are travelling towards each other. Blue wave always has a positive peak and the red wave always has a negative peak.

Now imagine these waves are moving through a rope. If blue waves will try to move the rope in positive direction, the red wave will pull it down, and thus the two waves will cancel the effect of each other. Thus resulting in a destructive interference. 

7 0
3 years ago
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A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration?
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Answer:

{ \boxed{ \bold{ \sf{Acceleration \: ( \: a) = 8 \: m/ {s \: }^{2} }}}}

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♨ Question :

  • A car starts from rest and is moving at 60.0 m/s after 7.50 s. What is the car's average acceleration ?

♨ \underbrace{ \sf{Required \: Answer : }}

☄ Given :

  • Initial velocity ( u ) = 0
  • Final velocity ( v ) = 60.0 m/s
  • Time ( t ) = 7.50 s

☄ To find :

  • Acceleration ( a )

✒ We know ,

\boxed{ \underline{ \bold{ \sf{Acceleration \: ( \: a) =  \frac{Final velocity ( v )  - Initial velocity ( u)}{t} }}}}

Substitute the values and solve for a.

➛ \sf{a =  \frac{60.0 - 0}{7.50}}

➛ \sf{a =  \frac{60.0}{7.50}}

➛ \boxed{ \boxed{ \sf{a = 8 \: m/ {s \: }^{2} }}}

---------------------------------------------------------------

✑ Additional Info :

  • When a certain object comes in motion from rest , in the case , initial velocity ( u ) = 0
  • When a moving object comes in rest , in the case , final velocity ( v ) = 0
  • If the object is moving with uniform velocity , in the case , u = v.
  • If any object is thrown vertically upwards in the case , a = -g
  • When an object is falling from certain height , in the case , final velocity at maximum height ( v ) = 0.

Hope I helped!

Have a wonderful time ツ

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4 0
2 years ago
41. 2072 Set E Q.No. 11 A source of sound produces a note of
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A. is the answer for this
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6 0
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Answer:

rate=0.093 s⁻¹

Explanation:

Given Data

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Solution

As we know that

e^{-kt^{n} } =1-y\\t^{n}=-\frac{ln(1-y)}{k}\\  t=-(\frac{ln(1-y)}{k} )^{\frac{1}{n} }\\ t=-(\frac{ln(1-0.5)}{0.006} )^{\frac{1}{2} }\\t=10.74 seconds\\rate=\frac{1}{t}\\ rate=\frac{1}{10.74} \\rate=0.093s^{-1}

8 0
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