We need to find the center and the radius of

The general circle equation is the following

where
(h,k) is the center and
r is the radius
1. rearrange the equation

2. Add 25 on both sides

3. Factor

Now we have an equation that is very similar to the circle equation, so let's compare them
Center -> (h,k) = (5,-11)
radius -> r = 5
Answer:
y = 9
Step-by-step explanation:
So if x = 3, we can sub that into the equation.
This gives us:
6.4 (* 3) + 2.8y = 44.4
so:
19.2 + 2.8y = 44.4
25.2 = 2.8y
so
y = 9
Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane
, then r will have the next parametric equations:

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

Substitute the value of
in the parametric equations:

Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane

Y/-2 + 5 = 13
y/-2 = 13 - 5 = 8
y = -2(8) = -16
y = -16
Answer:
-4/3 = y
Step-by-step explanation:
-1/2 = 3/8y
Multiply each side by 8/3 to isolate y
-1/2 * 8/3 = 3/8y * 8/3y
-8/6 =y
-4/3 = y