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Shkiper50 [21]
3 years ago
7

PLEASE HELP!! If the endpoints of have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of ?

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

M refers to midpoint.

A(9, 8) \\B(-1, -2) \\M(\frac{x_1-x_2}{2}, \frac{y_1-y_2}{2}) \\M(\frac{9-(-1)}{2}, \frac{8-(-2)}{2}) \\M(\frac{10}{2}, \frac{10}{2})\Longrightarrow\boxed{M(5, 5)}

Hope this helps.

r3t40

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X + 25/-8 = -6 Solve for x.<br> Simplify your answer as much as possible.
balandron [24]

Step-by-step explanation:

if there is nothing missing, we have

x + 25/-8 = -6

in order to compare or add or subtract fractions, we need to bring them all to the same denominator (bottom part).

remember, integer numbers are fractions too. like here

-6 = -6/1

25/-8 = -25/8

so, how can we bring -6/1 to .../8 ?

by multiplying 1 by 8.

but we cannot multiply only the denominator by 8. otherwise we would suddenly have

-6/8

and is -6/8 = -6/1 ? no, certainly not.

to keep the original value of the fraction we have to do the same multiplication also with the numerator (top part).

so, we actually do

-6/1 × 8/8 = -48/8

with this little trick we have now .../8 to operate with, and our transformed fraction has still the same value

-6/1 = -48/8 indeed.

so, we have

x + -25/8 = -48/8

x - 25/8 = -48/8

x = -48/8 + 25/8 = -23/8

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Can i have some help i spent a lot of points and it didn't work :((((
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Answers for A:

Factored form: (x-2)(x+4)

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