Answer:
thanks happy holidays and have a good day
Yes she is correct..
the reason why is because if she gives her horse 2 apples a day for 10 days, she will have spent 20 apples.
and so to get the number of apples she has remaining after 10 days, just subtract 20 from 24:
24-20 = 4
and you get four. That means that after 10 days she will indeed have 4 apples left
Answer:
y=m+p
Step-by-step explanation:
take the p to the other side.
p crosses = sighn and becomes +
hence ans = y=m+ p
9514 1404 393
Answer:
B. 3x^2 +11x -20 = 0
Step-by-step explanation:
For solutions p and q, the quadratic will be
(x -p)(x -q) = 0
We notice that the leading coefficients of the offered answer choices are greater than 1, so it will be convenient to use a value that "clears fractions."
(x -4/3)(x -(-5)) = 0
3(x -4/3)(x +5) = 0 . . . . multiply by 3 to clear the fraction
(3x -4)(x +5) = 0 . . . . . . clear the fraction
3x(x +5) -4(x +5) = 0 . . use the distributive property
3x^2 +15x -4x -20 = 0 . . . . use the distributive property again
3x^2 +11x -20 = 0 . . . . collect terms
_____
The constant in the product of factors is the product of roots:
(x -p)(x -q) = x^2 -(p+q)x +pq
Here, that would mean the constant would be (4/3)(-5) = -20/3.
If we compare the above quadratic to the standard form:
ax^2 +bx +c = 0
we find that we can divide the standard form equation by 'a' to get ...
pq = c/a
That is, c/a = -20/3, so we might start looking for an answer choice that has a leading coefficient of a=3 and a constant of c=-20.
Answer: hello your question is poorly written hence I will provide the required matrix
answer :
A = ![\left[\begin{array}{ccc}1&0&1\\0&1&1\\1&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%261%5C%5C0%261%261%5C%5C1%26-1%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given that the basis of the orthogonal complement have been provided already by you in the question I will have to provide the Matrix
The required matrix
column1 = column 3 - column2
where column 3 and column 2 are the basis of the orthogonal complement of the column space of the Matrix
