An A-frame cabin is 26.23 feet high at the center and the angle the floor makes with the base is 53. How

Mathematics

1 answer:

Vsevolod [243]4 years ago

7 0

Answer:

solution,

$tan \: theta = \frac{perpendicular}{base} \\ tan \: (53) = \frac{bc}{ac} \\ tan \: (53) = \frac{26.23}{ac} \\ ac = \frac{26.23}{0.4311} \\ ac = 60.84 \: feet$

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Can someone please answer. There is one problem. There's a picture. Thank you!

Nookie1986 [14]

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   $s = \frac{19\pi}{36}$
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Radians: $s = \theta r$
$s = \frac{95}{6}(6)$
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Arc Length = $\frac{\theta}{360} * C$
Arc Length = $\frac{95}{360} * 2(3.14)(6)$
Arc Length = $\frac{19}{72} * 2(18.84)$
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The answer is A.

3 0

3 years ago

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Use the power reducing formula to rewrite the expression in therms of first powers of hte cosines of ultiple angles 3cos^4x.

Oxana [17]

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