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rodikova [14]
3 years ago
12

Which option is an element?

Chemistry
2 answers:
insens350 [35]3 years ago
3 0

Answer:

Explanation:

water

mezya [45]3 years ago
3 0
D. Water should be correct lmk if I’m wrong
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A prism refracts white light into rainbow colors because
gogolik [260]

Because each color is refracted differently, each bends at a different angle, resulting in a fanning out and separation of white light into the colors of the spectrum. Water droplets in the air can act in a manner similar to that of a prism, separating the colors of sunlight to produce a spectrum known as a rainbow.

5 0
4 years ago
Calculate the [OH-] and the pH of 0.035 M KOH.
DanielleElmas [232]

Answer:

pH

= 12.54

OH- concentration 28.84

Explanation:

KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1

In any aqueous solution, the H3O+ and OH - must satisfy the following condition -

[ H_3O^+] [OH^-] = k_w

[ H_3O^+] = \frac{k_w}{ [OH^-]}

[H_3O^+]  = \frac{1 * 10^{-14}}{3.5 *10^{-2}[H_3O^+]  = 2.857 * 10^{-13} M

pH =

- log [ H_3O^+]\\- log [2.857 * 10^{-13}]

pH

= - [-12.54]\\= 12.54

pOH = 14 - pH

pOH

= 14 - 12.54\\= 1.46

OH concentration = antilog 1.46

OH- concentration 28.84

5 0
4 years ago
If 34.5 g of Copper reacts with 70.2 g of silver nitrate, according to the following
Vlada [557]

Answer:

44,55 can be produced.

Explanation:

First, we balanced the equation

1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag

Then, we find the moles of each reagent

mol Cu = \frac{34,5g}{63,55\frac{g}{mol} } = 0,543 mol\\

mol AgNO3 = \frac{70,2g}{169,87\frac{g}{mol} } = 0,413 mol\\

Now, we find the limiting reagent from the quantities of product that can be formed from each reagent

mol AgNO3= 0,543mol Cu . \frac{2 mol AgNo3}{1 mol Cu} = 1,086 mol

mol Cu= 0,413 mol AgNO3 . \frac{1 mol Cu}{2 mol AgNO3} = 0,206 mol

1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent

the value of the limiting reagent determines the amount of product that is generated

∴ 0,413 mol of Ag can be produced

Ag = 0,413 mol . 107,87\frac{g}{mol} = 44,55g

Ag≈ 44,6g

4 0
4 years ago
Read 2 more answers
How many moles of HCl are required to react with 1 g of zinc?
torisob [31]

Answer:

Explanation:

To solve problems like this, the very first thing to do is to write out the balanced equation for the process. The reaction is

Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g)

and the balanced equation is

Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

So, by examining the stoichiometry, you can see that for every mole of Zn, two moles of HCl will be required. In turn, we need to know the number of moles of Zn is represented by 10.4 g. The molecular weight of Zn is 65.38 g/mol so

moles of Zn = 10.4 g/65.38 g/mol = 0.159 moles

and, twice as many moles of HCl is required so

# of moles of HCl required = 2 * 0.159 = 0.318 moles

7 0
2 years ago
Which of the following correctly describes molecules of two different gases if they are at the same temperature and pressure?
Eduardwww [97]

Answer: C. They must have the same average kinetic energy.

Explanation: I got it right

5 0
3 years ago
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