Because each color is refracted differently, each bends at a different angle, resulting in a fanning out and separation of white light into the colors of the spectrum. Water droplets in the air can act in a manner similar to that of a prism, separating the colors of sunlight to produce a spectrum known as a rainbow.
Answer:
pH

OH- concentration 28.84
Explanation:
KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1
In any aqueous solution, the H3O+ and OH - must satisfy the following condition -
![[ H_3O^+] [OH^-] = k_w](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%5BOH%5E-%5D%20%3D%20k_w)
![[ H_3O^+] = \frac{k_w}{ [OH^-]}](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%3D%20%5Cfrac%7Bk_w%7D%7B%20%5BOH%5E-%5D%7D)
M
pH =
![- log [ H_3O^+]\\- log [2.857 * 10^{-13}]](https://tex.z-dn.net/?f=-%20log%20%5B%20H_3O%5E%2B%5D%5C%5C-%20log%20%5B2.857%20%2A%2010%5E%7B-13%7D%5D)
pH
![= - [-12.54]\\= 12.54](https://tex.z-dn.net/?f=%3D%20-%20%5B-12.54%5D%5C%5C%3D%2012.54)
pOH
pH
pOH

OH concentration 
OH- concentration 28.84
Answer:
44,55 can be produced.
Explanation:
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent


Now, we find the limiting reagent from the quantities of product that can be formed from each reagent


1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag =
= 44,55g
Ag≈ 44,6g
Answer:
Explanation:
To solve problems like this, the very first thing to do is to write out the balanced equation for the process. The reaction is
Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g)
and the balanced equation is
Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
So, by examining the stoichiometry, you can see that for every mole of Zn, two moles of HCl will be required. In turn, we need to know the number of moles of Zn is represented by 10.4 g. The molecular weight of Zn is 65.38 g/mol so
moles of Zn = 10.4 g/65.38 g/mol = 0.159 moles
and, twice as many moles of HCl is required so
# of moles of HCl required = 2 * 0.159 = 0.318 moles
Answer: C. They must have the same average kinetic energy.
Explanation: I got it right