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3 years ago

What is one similarity between metals and metalloids?

1 answer:

4 0

The correct answer that explains similarities between metal and Metalloids as regards the question is They both conduct electricity

Metalloids can be regarded as elements that are similar to metals, this is because they posses valence orbitals which is described as highly delocalized over macroscopic volumes.

As a result of this they can serve as electrical conductors.

metalloids posses small energy gap which is located between the valence band as well as the conduction band, as a result of this they are considered as intrinsic semiconductors when compare to pure conductors like metal.

Example of metal is Calcium, sodium and that of Metalloids are silicon and germanium

Therefore, metal and Metalloids are similar because of their conductivity of electricity

Learn more at: brainly.com/question/21036799?referrer=searchResults

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The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation

Reil [10]

Answer:

1027.62 g

Explanation:

For $B_2H_6$ :-

Mass of $B_2H_6$ = 296.1 g

Molar mass of $B_2H_6$ = 27.66 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{296.1\ g}{27.66\ g/mol}$

$Moles\ of\ B_2H_6= 10.705\ mol$

From the balanced reaction:-

$B_2H_6(g) + 3 O2_{(l)}\rightarrow 2 HBO_2_{(g)}+ 2 H_2O_{(l)}$

1 mole of $B_2H_6$ react with 3 moles of oxygen

Thus,

10.705 mole of $B_2H_6$ react with 3*10.705 moles of oxygen

Moles of oxygen = 32.115 moles

Molar mass of oxygen gas = 31.998 g/mol

<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>

8 0

3 years ago

To begin the experiment, 1.11g of methane CH4is burned in a bomb calorimeter containing 1000 grams of water. The initial tempera

navik [9.2K]

1. CH4 + 2O2 → CO2 + 2H2O
2. 10.80 degrees celsius
3. 45,187 J
4. 7,506 J
<span>5. 52,693 J </span>

6 0

3 years ago

The nonvolatile, nonelectrolyte testosterone, C19H28O2 (288.40 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressur

dolphi86 [110]

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

6 0

3 years ago

Explain

Trava [24]

There are so many routes by which water can move through the various stages in the water cycle.

<h3>What is the water cycle?</h3>

The water cycle has to do with the route of movement of water in the enviroment. We have to note that there are so many routes by which water can move through the various stages in the water cycle.

The sun supplies the energy that drives the water cycle. This is seen in the fact that the supply of energy from the sun is required for evaporation to take place.

Learn more about water cycle:brainly.com/question/1151425

#SPJ1

6 0

2 years ago

4. How many moles of KBr are found in 3 Liters of 0.4 M solution?

Allisa [31]

There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated by multiplying the molarity by the volume.

No. of moles = Molarity × volume

According to this question, 3L of a KBr solution are contained in a 0.4M.

no. of moles = 3L × 0.4M = 1.2moles

Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

Learn more about no. of moles at: brainly.com/question/14919968

4 0

3 years ago