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lana66690 [7]
3 years ago
10

What is one similarity between metals and metalloids?

Chemistry
1 answer:
Arturiano [62]3 years ago
4 0

The correct answer that explains similarities between metal and Metalloids as regards the question is They both conduct electricity

  • Metalloids can be regarded as elements that are  similar to metals, this is because they posses valence orbitals which is described as highly delocalized over macroscopic volumes.

  • As a result of this they can serve as electrical conductors.

  • metalloids posses small energy gap which is located between the valence band as well as the conduction band, as a result of this they are considered as  intrinsic semiconductors when compare to pure conductors like metal.

  • Example of metal is Calcium, sodium and that of Metalloids are silicon and  germanium

Therefore, metal and Metalloids are similar because of their conductivity of electricity

Learn more at: brainly.com/question/21036799?referrer=searchResults

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Romashka-Z-Leto [24]

Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

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We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
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Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
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Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

7 0
3 years ago
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