Answer: Hg +2
Explanation:
Hg+2 is formed when mercury loses two electrons.
Hg ------> Hg +2 + 2 e-
The values of N, log N and ln N are all worked out below.
We have the number N as 8.99
hence;
1) lnN = ln(8.99) = 2.196
log N = log (8.99) = 0.954
2) If we have ln N as 3.949
N = e^3.949 = 51.88
So;
log N = log (51.88) = 1.715
3) log N = 0.134
N = Antilog (0.134 ) = 1.36
ln N = ln (1.36) = 0.307
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<span>Answer:
Equation:
N2(g) + 3H2(g) → 2NH3(g)
Check for limiting reactant
Molar mass N2 = 28g/mol
mol N2 in 31,500g = 31,500/28 = 1,125 mol N2
This will require 1,125*3 = 3,375 mol H2
Molar mass H2 = 2g/mol
Mol H2 in 5,220g = 5,220/2 = 2,610 mol H2
The H2 is limiting
From the equation:
3 mol H2 will produce 2mol NH3
2610 mol H2 will produce 2610*2/3 = 1,740 mol NH3
Molar mass NH3 = 17g/mol
Mass of 1740 mol NH3 = 1740*17 = 29,580g NH3 produced
Mass of NH3 produced = 29.6kg</span>
The answer to your question is Sea Breeze.