Jimmy is employed on an assembly line. He receives $0.25 for each part that he works on. If he works on more than 150 Parts, his
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Hello!
The formula for circumference is
and the formula for area of a circle is 
. Armed with these formulas, we can begin to find the circumferences and areas of the circles.
20.
C =
C =
C =
C = 13(3.14)
C = 40.8
A =
A =
A =
A = 132.7
The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².
21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in
because the diameter is the radius × 2. For we do need to divide the diameter by 2.]
C =
C = 49.3
A =
A =
A =
A = 193.5
The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².
And that is all there is to it. I hope this helps you! (:
The formula for circumference is
20.
C =
C =
C =
C = 13(3.14)
C = 40.8
A =
A =
A =
A = 132.7
The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².
21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in
C =
C = 49.3
A =
A =
A =
A = 193.5
The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².
And that is all there is to it. I hope this helps you! (:
We are given parabola equation y=x^2-10x+30.
We need to convert it in vertex form y= a(x-h)^2+k.
We need to find the value of a, h and k to get the vertex form.
For the given equation y=x^2-10x+30, the coefficient of x^2 is 1.
Therefore, a=1.
Now, let us find values of h and k.
h = -b/2a.
h = -(-10)/2(1) = 5.
Plugging x=5 in given equation to get the value of k.
y= x^2-10x+30 => (5)^2 -10(5) +30 = 25 -50 +30 = 5.
Therefore, k =5.
Therefore, vertex (h,k) = (5,5).
<h3>So, the vertex form is </h3>