Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
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(See picture attached for sub-totals)
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a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%
Answer:
1.4
Step-by-step explanation:
............... ..............
0 0
Answer: Shania is correct.
Step-by-step explanation:
For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;
a/sin A = b/sinB
and
sin (angle) = opposite side/hypotenuse
cos (angle) = adjacent side/hypotenuse
tan (angle) = opposite/ adjacent
assuming a is the opposite side of angle A and b is also opposite of angle B
Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.
Hence, Shania is correct.
Answer:
the first answer is correct and brainliest plsss (^_^)
Step-by-step explanation:
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.