Question

Given f(x)= 2x-2/4 solve for f^-1(3)

Answer 1

Answer:

$f^{-1}(3)=7$

Step-by-step explanation:

Given : $f(x)=\frac{2x-2}{4}$

To Find: $f^{-1}(3)$

Solution:

$y=\frac{2x-2}{4}$

Replace x with y and y with x

$x=\frac{2y-2}{4}$

Now find the value of y

$\frac{4x+2}{2}=y$

$2x+1=y$

Thus $f^{-1}(x)=2x+1$

Now, $f^{-1}(3)=2(3)+1=6+1=7$

Hence $f^{-1}(3)=7$

Answer 2

F(x)=y=(2x-2)/4
f^-1(x)=x=(2y-2)/4
4x=2y-2
4x+2=2y
f^-1(x)=y=2x+1
f^-1(3)=2(3)+1
=6+1
=7