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Oksanka [162]
3 years ago
15

precalculus help! i'm having some trouble with my summer assignment. help would be very appreciated :)))

Mathematics
2 answers:
Anni [7]3 years ago
5 0

Problem 3:

We are given the following complex number and I'm assuming we want to simplify it:

\dfrac{5+i}{6+i}

Using the complex arithmetic rule (research about this if you're not familiar with it, it's very helpful):

=\dfrac{(5\times6+1)+(6-5)i}{6^2+1^2}

=\dfrac{31+i}{37}

Simplifying gives us:

=\dfrac{31}{37}+\dfrac{1}{37}i

Problem 6:

You seem to have done this problem correctly

\sqrt[8]{8y^{16}}

Expanding gives us:

=\sqrt[8]{y^{16}}\times\sqrt[8]{8}

=y^2\sqrt[8]{8}

This can't be simplified further as the 8th root of 8 gives us an irrational number

Let me know if you need any clarifications or extra help, thanks!

IgorC [24]3 years ago
4 0

6.

y^2\sqrt[8]{8}

Step-by-step explanation:

\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}

Since there are eight y's in two groups we can take them out which turns into

y^2\sqrt[8]{8}

:)

3.

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Giveing 15 points.Use the rectangle to find the measure of the following angles measure ane BAC=25
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1) All angles of a rectangle are right angles, so the measure of angle CBA is 90 degrees.

2) Since all angles of a rectangle are right angles, angle BAD measures 90 degrees. Subtracting the 25 degrees of angle BAW from this, we get that angle CAD has a measure of 65 degrees.

3) Opposite sides of a rectangle are parallel, so by the alternate interior angles theorem, the measure of angle ACD is 25 degrees.

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A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches

The formula used to calculate the rectangular base of a rectangular pyramid =

Length × Width

Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

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Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

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= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

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The formula for the total surface area of the rectangular pyramid is given as

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Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

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