precalculus help! i'm having some trouble with my summer assignment. help would be very appreciated :)))
2 answers:
Problem 3:
We are given the following complex number and I'm assuming we want to simplify it:

Using the complex arithmetic rule (research about this if you're not familiar with it, it's very helpful):


Simplifying gives us:

Problem 6:
You seem to have done this problem correctly
![\sqrt[8]{8y^{16}}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8y%5E%7B16%7D%7D)
Expanding gives us:
![=\sqrt[8]{y^{16}}\times\sqrt[8]{8}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B8%5D%7By%5E%7B16%7D%7D%5Ctimes%5Csqrt%5B8%5D%7B8%7D)
![=y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=%3Dy%5E2%5Csqrt%5B8%5D%7B8%7D)
This can't be simplified further as the 8th root of 8 gives us an irrational number
Let me know if you need any clarifications or extra help, thanks!
6.
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
Step-by-step explanation:
![\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%7D)
Since there are eight y's in two groups we can take them out which turns into
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
:)
3.
You might be interested in
Answer:
No solution
Step-by-step explanation:
since it equals a negative 3 in the original equation it cannot be solved
Answer:
14 (3 sqrt x)
Step-by-step explanation:
-4x + 8y = 2
-4x + 4x + 8y = 2 + 4x
8y = 4x + 2
8 8
y = ¹/₂x + ¹/₄
Answer:
1, 0.4
2, 0.004
3, 0.04
Step-by-step explanation:
hope this helps. :)