Which is the solution for log(4x-1)=log(x+1)+log2?
2 answers:
Answer:
It's x=3/2
Step-by-step explanation:
Took it just now
Answer:
x = 1.5
Step-by-step explanation:
Solution
log(4x - 1) - log(x+1) = log2 log(x + 1) was subtracted from both sides log[(4x - 1)/log(x+1)] = log2 Subtaction of logs means division (4x - 1) / (x + 1) = 2 Take the antilog of both sides 4x - 1 = 2(x + 1) Remove the brackets 4x - 1 = 2x + 2 Add 1 to both sides 4x = 2x + 3 Subtract 2x 4x - 2x = 3 2x = 3 Divide by 2 x = 3/2 Answer Check
<em><u>Left Hand Side</u></em>
log(4*1.5 - 1) log(6 - 1) log(5) <em><u>Right Hand Side</u></em>
log(1.5 + 1) + log(2) log(2.5) + log(2) log2*2.5 log 5 And they check
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