Try this option:
note, that the difference between 8 and 10 is 2, between 9 and 12 is 3, between 11 and 16 is 5. It is possible when f(x) is linear function, 2x-6, therefore f(14)=2*14-6=22

Answer: 22.

6 0

3 years ago

Edi plays 1/4 of a song in 1/8 of a minute how many minutes will he need to play a full song

Neporo4naja [7]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

$first \: \: \: \frac{1}{4} \: \: \:of \:a \: song \: needs \: \frac{1}{8} \: \: minute. \\ \\ second \: \: \: \frac{1}{4} \: \: of \: a \: song \: needs \: \frac{1}{8} \: minute \: too. \\ \\ also \: the \: third \: and \: fourth \: \: \: \frac{1}{4} \: \: \: of \: a \: song \: need \: \frac{1}{8} \: minute \: . \\ \\ so \: we \: have \: completly \: have \: 4 \times \frac{1}{8} \\ \\ which \: means \: edi \: needs \: 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2} \: minute \: to \: play \: all \: the \: song.$

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0

3 years ago

One Endpoint is 9,18 and the midpoint is 14,16 what the other end point

Valentin [98]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 9}}\quad ,&{{ 18}})\quad 
% (c,d)
&({{ x}}\quad ,&{{ y}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

$\bf \left( \cfrac{x+9}{2}~,~\cfrac{y+18}{2} \right)=\stackrel{\textit{midpoint}}{(14,16)}\implies 
\begin{cases}
\cfrac{x+9}{2}=14\\\\
x+9=28\\
\boxed{x=19}\\
-------\\
\cfrac{y+18}{2}=16\\\\
y+18=32\\
\boxed{y=14}
\end{cases}$

7 0

3 years ago