What is (4x+1)(4x+1)
2 answers:
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Answer: option c
Step-by-step explanation:
Find the x-intercept and y-intercept of each line.
To find the x-intercept, substitute into the equation and solve for "x".
To find the y-intercept, substitute into the equation and solve for "y".
- For the first equation:
x-intercept
y-intercept
Graph a line that passes through the points (7.25, 0) and (0, 9.66)
- For the second equation:
x-intercept
y-intercept
Graph a line that passes through the points (0.5, 0) and (0, -0.33)
Observe the graph attached. You can see that point of intersection of the lines is (5,3); then this is the solution of the system. Therefore:
To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6