The term of this sequence is:
<span>-(17/30)n^5+(113/12)n^4-(173/3)n^3+(1915/12)n^2-(5813/30)n+85 </span>
<span>Therefore,term number 7 is:-146/1=-146 </span>
Answer:
Step-by-step explanation:
⇒ 
or
(Answer)
9514 1404 393
Answer:
F HL
Step-by-step explanation:
No right angle is shown, so the HL theorem cannot be used.
|x|=absoulte value of x which means whatever x is, make it positive
so first solve any division/multiplication
the only one is 12/46=6/23
so we do the absoulte value signs
-3+45-(-14)
-(-14)=+14
-3+45+14=56
absoulute value of 56=56
56+(-|-87+6/23|)
-87+6/23=-86 and 17/23
absoulte value of -86 and 17/23=86 and 17/23
there is a negative sign in front of the absoulte vaulue so make it negative
56-86 and 17/23=-30 and 17/23 or about -30.73913
Answer:
<em>First even integer: 6</em>
Step-by-step explanation:
<u>Inequalities</u>
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:

Operating:

Subtracting 2 and 2x:

Simplifying:

Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.