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seraphim [82]
3 years ago
10

If the graph of f(x) is: Which of the following is the graph of −f(−x)?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

D.

Step-by-step explanation:

Since negative times negative equals positive the graph will still be the same meaning -f(-x)=f(x)

Since the graph is the same the answer is D.

Hope this helps!

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F=(9/5) C +32, C=15 Can you show me what a graph looks like?
CaHeK987 [17]

Answer:

Step-by-step explanation:

F=(9/5) C +32 has the form of the equation of a straight line:  y = mx + b, where m is the slope and b is the y-intercept.  By comparing these two equations we see that the slope, m, is (9/5) and the y-intercept is 32 (or (0, 32)).

To graph this, first locate the y-intercept (0, 32); put a dark dot there.  Since the slope is 32, or 32/1, move your pencil point 1 unit to the right, from (0, 32) to (1, 32), and then from (1, 32) move y our pencil point 32 units upward.  Plot another dark dot there and then draw a straight line through these two points.

We can evaluate the given function F=(9/5) C +32 at C = 15 by replacing C in the formula with 15:  F = (9/5)(15) + 32, or F = 59.

8 0
3 years ago
The following list shows the number of video games sold per day at a video store.
TEA [102]
Here is what your frequency/cumulative frequency table would look like.  The cumulative frequency is where you add all the frequencies from before it to get a sum after each interval.

              <u> Frequency    </u>       <u>Cumulative Frequency</u>
0-25             8                              8
26-50           0                              8
51-75           4                             12
76-100         2                             14
4 0
3 years ago
Compute 1240.64/6.4 round the answer appropriately <br><br>thank you
liubo4ka [24]
1240.64 / 6.4 = 193.85

193.85 rounded is 194
3 0
3 years ago
without building the graph, find the coordinates of the point of intersection of the lines given by the equation y=3x-1 and 3x+y
DaniilM [7]
<h2><u>1. Determining the value of x and y:</u></h2>

Given equation(s):

  • y = 3x - 1
  • 3x + y = -7

To determine the point of intersection given by the two equations, it is required to know the x-value and the y-value of both equations. We can solve for the x and y variables through two methods.

<h3 /><h3><u>Method-1: Substitution method</u></h3>

Given value of the y-variable: 3x - 1

Substitute the given value of the y-variable into the second equation to determine the value of the x-variable.

\implies 3x + y = -7

\implies3x + (3x - 1) = -7

\implies3x + 3x - 1 = -7

Combine like terms as needed;

\implies 3x + 3x - 1 = -7

\implies 6x - 1 = -7

Add 1 to both sides of the equation;

\implies 6x - 1 + 1 = -7 + 1

\implies 6x = -6

Divide 6 to both sides of the equation;

\implies \dfrac{6x}{6}  = \dfrac{-6}{6}

\implies x = -1

Now, substitute the value of the x-variable into the expression that is equivalent to the y-variable.

\implies y = 3(-1) - 1

\implies     \ \ = -3 - 1

\implies     = -4

Therefore, the value(s) of the x-variable and the y-variable are;

\boxed{x = -1}   \boxed{y = -4}

<h3 /><h3><u>Method 2: System of equations</u></h3>

Convert the equations into slope intercept form;

\implies\left \{ {{y = 3x - 1} \atop {3x + y = -7}} \right.

\implies \left \{ {{y = 3x - 1} \atop {y = -3x - 7}} \right.

Clearly, we can see that "y" is isolated in both equations. Therefore, we can subtract the second equation from the first equation.

\implies \left \{ {{y = 3x - 1 } \atop {- (y = -3x - 7)}} \right.

\implies \left \{ {{y = 3x - 1} \atop {-y = 3x + 7}} \right.

Now, we can cancel the "y-variable" as y - y is 0 and combine the equations into one equation by adding 3x to 3x and 7 to -1.

\implies\left \{ {{y = 3x - 1} \atop {-y = 3x + 7}} \right.

\implies 0 = (6x) + (6)

\implies0 = 6x + 6

This problem is now an algebraic problem. Isolate "x" to determine its value.

\implies 0 - 6 = 6x + 6 - 6

\implies -6 = 6x

\implies -1 = x

Like done in method 1, substitute the value of x into the first equation to determine the value of y.

\implies y = 3(-1) - 1

\implies y = -3 - 1

\implies y = -4

Therefore, the value(s) of the x-variable and the y-variable are;

\boxed{x = -1}   \boxed{y = -4}

<h2><u>2. Determining the intersection point;</u></h2>

The point on a coordinate plane is expressed as (x, y). Simply substitute the values of x and y to determine the intersection point given by the equations.

⇒ (x, y) ⇒ (-1, -4)

Therefore, the point of intersection is (-1, -4).

<h3>Graph:</h3>

5 0
2 years ago
A pair of parallel lines is cut by a transversal as shown in the figure. Match the angles with their corresponding angles.
garri49 [273]
D and H are corresponding
G and C are corresponding
E and A are corresponding
B and F are corresponding
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3 years ago
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