Answer:
2/5
Step-by-step explanation:
2 / 4 could be divided by two in both sides.
2 ÷ 2 = 1
4 ÷ 2 = 2
2/4 = 1/2
Same goes for 2/8 and 2/6
2 ÷ 2 = 1
8 ÷ 2 = 4
2/8 = 1/4
2 ÷ 2 = 1
6 ÷ 2 = 3
2/6 = 1/3
2/5 however, could not be divided by two on both sides because there is 5 and it is not a factor of 2. So it is in its simplest form
Answer:
Step 1: 8 + 16x Step 2: 4(4) + 4(12x) Step 3: 4(4 + 12x) Step 4: Dimensions of the rectangle are 4 and 4 + 12x In which step did the student first make an error and what is the correct step? Step 3; 4 + (4 + 12x) Step 3; 4 + (4 ⋅ 12x) Step 2; 4(2) + 4(4x) Step 2; 4(2) + 4x(2)
Answer:5y=x-35
Step-by-step explanation:
The given line passes through the points
,
.
Let the slope of the line be
.
If a line passes through
and
,then

So,
Y-intercept of a line is defined as the y-coordinate of the point where the line touches y axis.
Let the y intercept be 
From the graph,
The equation of the line with slope
and y-intercept
is 
So,

Answer:
- <u>Question 1:</u>
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- <u>Question 2:</u>
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- <u>Question 3:</u>
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- <u>Question 4:</u>
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Explanation:
<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>
<u></u>
a) By definition: 
b) Given: 
c) By substitution: 
<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>
a) <u>Separate variables</u>

b)<u> Integrate</u>


c) <u>Antilogarithm</u>



<u>Question 3. Which particular solution matches the additional information?</u>
<u></u>
Use the measured rate of 4 grams per hour after 3 hours

First, find the mass at t = 3 hours

Now substitute in the general solution of the differential equation, to find A:

Round A to 1 significant figure:
<u>Particular solution:</u>

<u>Question 4. What was the mass of the bacteria at time =0?</u>
Substitute t = 0 in the equation of the particular solution:

Answer:
Step-by-step explanation:
put it on a coorinate grid,
circle circumference = 2*pi*r = 100.53
so the arc 19.2/100.53 = about 0.15 times the circumference of the circle
0.15*2pi = angle AOB in radians = 0.97
length DE is like 7.44
angle DOE is approx 0.485 radians beacuse it's half of angle AOB
area of shaded region is 804.2477 probably. I'm not sure about this last one sorry I think my calculator messed up