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artcher [175]
3 years ago
11

If on a scale 75 feet are represented by 45 inches, then a scale of 1/5 inch represents how many feet?

Mathematics
1 answer:
liberstina [14]3 years ago
6 0

A scale of \frac{1}{5} inch represents \frac{1}{3} feet

<em><u>Solution:</u></em>

Given that,

On a scale drawing

45 inches represented = 75 feet

We have to find a scale of \frac{1}{5} inch in feet

Let us first find 1 inch in feet

From given,

45 inches = 75 feet

Therefore,

1 \text{ inches } = \frac{75}{45} \text{ feet }

Now find for \frac{1}{5} inch in feet

1 \times \frac{1}{5} \text{ inches } = \frac{75}{45} \times \frac{1}{5} \text{ feet }\\\\\frac{1}{5} \text{ inches } = \frac{75}{225} \text{ feet }\\\\\frac{1}{5} \text{ inches } = 0.33 \text{ feet }\\\\\frac{1}{5} \text{ inches } = \frac{1}{3} \text{ feet}

Thus a scale of \frac{1}{5} inch represents \frac{1}{3} feet

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Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

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\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

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