Answer: 3
Step-by-step explanation:
The 3D vector consists of 3 axes, let's say x, y and z.
Now, a vector P lies in all of them.
So, the angle it makes with x axis is α
The angle it makes with y axis is β
The angle it makes with z axis is γ
So, to determine the Cartesian components or to resolve the vector into it's Cartesian components we need 3 angles with each axis.
Answer:
y = 4
Step-by-step explanation:
6y + 30 = 54
subtract 30 from each side
6y = 24
divide each side by 6
y = 4
The answer would be “b” because in translations when the question says up it’s referring to y
Therefore ![\theta = 30^\circ](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2030%5E%5Ccirc)
Step-by-step explanation:
Given,
![4\sqrt{3 } =8 cos \theta](https://tex.z-dn.net/?f=4%5Csqrt%7B3%20%7D%20%3D8%20cos%20%5Ctheta)
![\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}](https://tex.z-dn.net/?f=%5CLeftrightarrow%20cos%20%5Ctheta%20%3D%5Cfrac%7B4%5Csqrt%7B3%7D%20%7D%7B8%7D)
![\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5CLeftrightarrow%20cos%20%5Ctheta%20%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
![\Leftrightarrow cos \theta =cos 30^\circ](https://tex.z-dn.net/?f=%5CLeftrightarrow%20cos%20%5Ctheta%20%3Dcos%2030%5E%5Ccirc)
![\Leftrightarrow \theta = 30^\circ](https://tex.z-dn.net/?f=%5CLeftrightarrow%20%20%5Ctheta%20%3D%2030%5E%5Ccirc)
Therefore ![\theta = 30^\circ](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2030%5E%5Ccirc)
I got 8.65 if this any help