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dimulka [17.4K]
3 years ago
14

800,000,000,000 + 20,000,000,000 + 3,000,000,000 + 50,000,000 + 4,000,000 + 600,000 + 50,000 + 8,000 + 700 + 80 + 6

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0
823054658786 is the answer to your question
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If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact. f(
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By definition, a polynomial is an expression with more than one term. That is a monomial. We have names for 2-termed polynomials (binomials) and 3-termed polynomials (trinomials), but that's where the naming stops and they all are called polynomials after that. Our degree is the same as the highest exponent. So our degree is a fifth degree. The leading coefficient is the number that starts out the whole polynomial AS LONG AS IT IS IN STANDARD FORM. If our polynomial started with the -4x^4, our leading coefficient would NOT be -4 since the highest degree'd term will always come first in standard form. Your choice for your answer is the first one given. Degree: 5 Leading Coefficient: -13.

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Find the domain of the function (13/x-11)
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The domain of 13/x - 11 is all real numbers except x cannot equal zero
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Rocco earned $5 for every A he received on his report
Morgarella [4.7K]

Answer:

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Rewrite expression in the form k*z^n
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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

  • The range of the function is all real numbers less than or equal to 9.
<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

  • The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c  with the vertex \mathbf{(x_v,y_v)}

  • If a < 0, then the range is f(x) ≤ \mathbf{y_v}
  • If a > 0, then the range f(x) ≥  \mathbf{y_v}
  • Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

\mathbf{x_v = -\dfrac{b}{2a}}

Thus,

  • vertex \mathbf{(x_v,y_v)} = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

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