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3 years ago

6

Tell whether the sequence , , , . . . is arithmetic, geometric, or neither. Find the next three terms of the sequence. A. neithe

r; 7, -20, 61 B. geometric;7, -20, 61 C. arithmetic; , , D. geometric; , ,

1 answer:

Nastasia [14]3 years ago

5 0

Looking at the predicted three terms, the sequence seems to neither arithmetic nor geometric.<span />

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Which pairs make the equation x-9y=12 true

Serggg [28]

Answer:

(12,0), (3, -1) (0,-4/3)

Step-by-step explanation:

To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.

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last season, a pitcher had an earned run average of 2.80 and allowed 70 earned runs. How many innings did the pitcher pitch last

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4 innings and that's with the 70 earned runs

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3 years ago

Mrs moretti is making welcome bags to give to the 18 students in his homeroom on the first day of school. He puts m mechanical p

julsineya [31]

Answer:

b.) 18(m+2m)

d.) 18m+18(2m)

e.) 54m

Step-by-step explanation:

Given;

total number of Mr Moretti's students = 18

number of mechanical pencils for each student = m

total number of mechanical pencils for all the students = 18m

number of regular pencils for each student = 2m

total number of regular pencils for all the students = 18(2m)

The total number of pencils given to all the 18 students by Mr Moretti is given by;

T = Total mechanical pencils + total regular pencil

T = 18m + 18(2m)

T = 18(m + 2m)

T = 18(3m)

T = 54m

Therefore, based on the expressions above, the correct options include;

b.) 18(m+2m)

d.) 18m+18(2m)

e.) 54m

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3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

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3 years ago

Please find the value of A and B

lesya [120]

Here's a photo of the solution. Hope this helps and please give brainlist!

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2 years ago

Read 2 more answers