Because they do not have like bases.
In the problem, two legs measurement were given such as:
Leg 1 = 12 inches
Leg 2 = 15 inches
We need to solve for the third leg. Since it is a right triangle, we can use Pythagorean theorem in solving the missing leg:
c²=b²+a²
When we assume that the third leg is the "c", we can for the value such as:
c² = 12²+15²
c=19.21
When we assume that the third is either "a" or "b":
15² =a² + 12²
a=9
Then, the possible measurement of the third leg is 9 or 19.21.
The difference between the two possible answer is shown below:
Difference = 19.21 -9 = 10.21
Difference =10.21
With polynomials the degree is the highest power x or whatever the variable is raised to. In this case, the degree is 3 since the highest power x is raised to is x^3
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
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The amplitude can be found by using the following:
Our maximum is 44 and our minimum is 20.
The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~
