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DedPeter [7]
2 years ago
7

To support an internet client, you must have six elements. the first three -- a computer, an operating system and tcp/ip -- are

generally acquired when you buy a computer. which choice lists the other three elements you need to support an internet client?
Computers and Technology
1 answer:
UkoKoshka [18]2 years ago
6 0
<span>Client software, Internet connection and Internet address</span>
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What is the MINIMUM number of paths that would need to be broken to prevent Computing Device A from connecting with Computing De
Sveta_85 [38]

Answer:

The answer is "Option c".

Explanation:

In the given question the device A is connected by 3 wires, contributing all of them, which also includes several connector paths. When all the wires of A are broken down, and if all of this leaves no routes that can be used. Even so, if it is done to E, it's also linked to four different routes. Its solution would've been C because its value will be the MINIMUM.

4 0
2 years ago
Read 2 more answers
By what decade were books readily available to the public across the United States and Europe? A. 1690 B. 1750 C. 1860 D. 1820
sladkih [1.3K]

Answer: 1820

Explanation:

I <u>believe</u> the answer is the 1820, as the introduction of steam powered printing presses and steam powered paper mills significantly lowered the cost of books to decrease and significantly increased their circulation/availability.

hope this  helps

-lvr

6 0
3 years ago
Give a tight bound on the number of times the z = z + 1 statement is executed. i = 2 while ( i &gt; 1 ) { i = floor(i/2) z = z +
Alinara [238K]

Answer:

zero ( 0) times.

Explanation:

In the code;

i = 2

while ( i > 2){

     i = floor( i/2 );

     z = z + 1;

}

the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.

But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.

4 0
2 years ago
If one wanted to use the best method to get storage into long-term memory, one would use _________. maintenance rehearsal rote r
anzhelika [568]

Answer:

elaborative rehearsal

Explanation:

when it comes to storage of information or data into long term memory then elaborative rehearsal plays an important role.

Elaborative rehearsal is a technique which focuses on thinking about the piece of information or data's meaning which is to be stored in long term memory and linking it with the information or data which is already present or stored.

7 0
2 years ago
Write a C++ programthat reads in the side of a square and prints out a pattern on$
AnnZ [28]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int side;

   //print the message

   cout<<"Please enter the side of square: ";

   cin>>side;  //read the vale and store in the variable.

   // for loop

   for(int i=1;i<=side;i++){  //lop for rows

       for(int j=1;j<=side;j++){   //loop for column

           cout<<"$";  //print the '*'

       }

       cout<<endl;

   }

}

Explanation:

Create the main function and declare the variable side.

print the message on the screen for the user and then store value enter by the user on the variable side.

take the nested for loop for print the pattern.

nested for loop means, loop inside another loop it is used for print the pattern having rows and columns.

the first loop updates the row number and the second the loop print the character '$' in the column-wise.

in the code,

if i = 1, for loop check the condition 1 <= 5 if the value of side is assume 5.

condition is true and the program moves to the second for loop and starts to print the character '$' five times after that, print the new line.

then, the above process repeat for different rows and finally, we get the pattern in square shape.

7 0
2 years ago
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