Answer:
The presence of an additional chromosome
Explanation:
Look at "pair" 21. See how there are THREE chromosomes instead of TWO? Normally, there would only be two chromosomes in each pair but this karyotype shows a trisomy (see def. below) of the 21st pair. This was caused by a nondisjunction mutation of the 21st pair. The is also the karyotype of a person with Down's Syndrome.
Definition of Trisomy:
A condition of the presence of three chromosomes in a pair instead of two. This normally causes developmental irregularity.
Answer: Can you say which five scenarios is the project talking about-?
The correct answer to your question is B. Glycine-Tyrosine-Glycine-Histidine-Histidine.
You can find this by taking groups of codons starting with the first group (GGC). GGC is located under Glycine so Glycine will therfore be an amino acid found in the protein. Continue doing this with the next codons to come up with the answer.
I hope this isn't too late and still helps!
:)
Answer: Sediment. Hope this helps :^)
Answer:
5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)
6.) Frequency of R: 0.5
7.)Frequency of R: 0.5
8.)Frequency of R: 0.375
Explanation:
5.) If R and B code for the different forms of the same protein then they are only a few possible out comes
6.) First calculate the total alleles in population
allele R= 40
Allele B=40
total allele = R+B= 40+40
=80
Now to find allele R frequency is:
(Total R alleles) / (Total allele in pop)
40/80=
0.5
7.)Calculate the total alleles
Alleles from for R
RR= 10
R=10x 2= 20
Multiply the value by 2 because there are 2 R alleles present in
RB=20
R=20
Number doesn't change there is only 1 R allele
Total R=20+20
=40
Alleles For B
BB=10
B=10×2
=20
Same thing here, two B alleles together so multiple by 2
RB=20
B=20
Total B= 20+20
=40
Total alleles in pop add
40+40
=80
Frequency of R
Total of R/Total Alleles
=40/80
=0.5
8.)Repeat the same thing in 7 but use different numbers
RR=10
R=10x2
=20
RB=10
R=10
Total R= 20+10
=30
