Question

What is the value of A when we rewrite (7/3)^x as A^2x?

Answer 1

$({ \frac{7}{3} })^{x} = {A}^{2x}$

$({ \frac{7}{3} })^{x} = {A}^{ {2}^{x} }$

$\frac{7}{3} = {A}^{2}$

$A = ± \sqrt{ \: \frac{7}{3} \: }$

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I think this is the correct answer.

And we're done.

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