Answer:
Step-by-step explanation:
Given
Required
Determine the smallest dimension to use
To answer this question, I'll make use of the attached figure as a point of reference.
The area of the printed matter is:
Substitute 150 for A1
Make H the subject
The area of the full paper is:
Substitute 150/W for H
Open brackets
Collect Like Terms
Differentiate with respect to w and set the result to 0
Set to 0
Collect Like Terms
Cross Multiply
Make the subject
Take positive square root of both sides
Recall that:
Hence, the smallest dimension of the paper is:
The area (A) of the rectangle is the product of its width (W) and length (L). Mathematically,
A = L x W
Substituting the given values,
A = (16^1/5) x (2^1/5)
Since they have the same exponents, the simplified expression for the area is,
A = 32^1/5
The value of area is 2. Thus, the answer is letter C.
Okay, so you what you would is solve one equation for Y=mx+b and then substitute this equation for Y so the answer would be Y=-3/2x + 20
And then you would do 2x-3(-3/2x+20)=-11 and you solve it for x
But to get y you would substitute what you got for x into ether equations.
Answer:
118°
Step-by-step explanation:
because 28 + 90 = 118