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bazaltina [42]
3 years ago
9

Find the area of the trapezoid. Please Help

Mathematics
2 answers:
Fudgin [204]3 years ago
5 0

Answer:

<h2>12</h2>

Step-by-step explanation:

RULE:

the area of the trapezoid = height × [(base1 + base2)÷2]

According to the given picture :

height = 3

base1 = 6

base2 = 2

therefore,

The area = 3×[(6+2)÷2]

              = 12

vitfil [10]3 years ago
4 0

Answer: 14 squared units

Step-by-step explanation:

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Answer:

\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\

Step-by-step explanation:

Factor constant terms:

-2(-4sin(2\theta)+sin(\theta))=0

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sin(\theta)-4sin(2 \theta)=0

Expand trigonometric functions using the fact:

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sin(\theta) (8cos(\theta)-1)=0

Split into two equations:

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For (1)

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cos(\theta)=\frac{1}{8}

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\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z

For (2)

Simply take the inverse sine of both sides

\theta = k \pi, \hspace{3}k\in Z

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\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\

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3 years ago
(5 + 6) - + (-5 - 6) + - (5 - - 6)<br><br> A.21<br> B.12<br> C.11<br> D.18
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Answer:

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Step-by-step explanation:

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Answer:

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